Maths > Circles > 2.0 Equation of circle in various forms

  Circles
    1.0 Definition
    2.0 Equation of circle in various forms
    3.0 Intercepts made by a circle on coordinate axis
    4.0 Position of a point with respect to a circle
    5.0 Maximum and minimum distance of a point from a circle
    6.0 Intersection of a line and a circle
    7.0 Length of intercept cutoff from a line by a circle or length of chord of a circle
    8.0 Equation of tangent to a circle
    9.0 Tangents from a point to the circle
    10.0 Length of tangent from a point to a circle
    11.0 Common Tangents
    12.0 Equation of common tangents
    13.0 Pair of tangents
    14.0 Normal to a circle at a given point
    15.0 Common chord of two circles
    16.0 Equation of chord joining two points on circle
    17.0 Equation of chord of circle whose midpoint is given
    18.0 Chord of contact
    19.0 Orthogonal Circles
    20.0 Director Circle
    21.0 Family of circles

2.4.1 Application of general form of circle
To find the equation of circle passing through three non-collinear points. (CONCEPT THROUGH QUESTIONS)

Method 1: Find the equation of circle passing through $(1,0)$, $(-1,0)$ and $(0,1)$.

Solution: Let the equation of circle passing through the given $3$ points in general form be $${x^2} + {y^2} + 2gx + 2fy + c = 0$$
The above equation satisfies all the $3$ points. Putting the values, we get
$${1^2} + {0^2} + 2 \times g \times 1 + 2 \times f \times 0 + c = 0$$ $$2g + c = - 1 \ldots \left( 1 \right)$$ $$ - {1^2} + {0^2} + 2 \times g \times - 1 + 2 \times f \times 0 + c = 0$$ $$ - 2g + c = - 1 \ldots \left( 2 \right)$$ $${0^2} + {1^2} + 2 \times g \times 0 + 2 \times f \times 1 + c = 0$$ $$2f + c = - 1 \ldots \left( 3 \right)$$
Adding $(1)$ and $(2)$, we get $c=-1$.
Subtracting $(1)$ and $(2)$, we get $g=0$.
Put the value of $c$ in $(3)$, we get $f=0$.
Therefore, the equation of circle passing through the given $3$ points is ${x^2} + {y^2} - 1 = 0$.


Method 2: Equation of circle passing through $(1,1)$, $(2,-1)$ and $(3,2)$.

Solution: Write the equation of circle in the form as shown below

$$\begin{gathered}\left| {\begin{array}{c}{{x^2} + {y^2}}&x&y&1 \\ {{1^2} + {1^2}}&1&1&1 \\ {{2^2} + {{\left( { - 1} \right)}^2}}&2&{ - 1}&1 \\ {{3^2} + {2^2}}&3&2&1 \end{array}} \right| = 0 \hspace{1em} \\\left| {\begin{array}{c}{{x^2} + {y^2}}&x&y&1 \\ 2&1&1&1 \\ 5&2&{ - 1}&1 \\ {13}&3&2&1\end{array}} \right| = 0 \hspace{1em} \\ \end{gathered} $$
Applying ${C_1} \to {C_1} - 2{C_4},{\text{ }}{C_2} \to {C_2} - {C_4}{\text{ and }}{C_3} \to {C_3} - {C_4}$
$$\left| {\begin{array}{c}{{x^2} + {y^2} - 2}&{x - 1}&{y - 1}&1 \\ 0&0&0&1 \\ 3&1&{ - 2}&1 \\ {11}&2&1&1 \end{array}} \right| = 0$$
Expand with respect to second row, we get
$$\left| {\begin{array}{c}{{x^2} + {y^2} - 2}&{x - 1}&{y - 1} \\ 3&1&{ - 2} \\ {11}&2&1 \end{array}} \right| = 0$$
Applying ${C_1} \to {C_1} - 3{C_2}{\text{ and }}{C_3} \to {C_3} - 2{C_2}$
$$\left| {\begin{array}{c}{{x^2} + {y^2} - 3x + 1}&{x - 1}&{2x + y - 3} \\ 0&1&0 \\ 5&2&5 \end{array}} \right| = 0$$
Expand with respect to second row, then
$$\left| {\begin{array}{c}{{x^2} + {y^2} - 3x + 1}&{2x + y - 3} \\ 5&5 \end{array}} \right| = 0$$ or, $$5\left| {\begin{array}{c}{{x^2} + {y^2} - 3x + 1}&{2x + y - 3} \\ 1&1 \end{array}} \right| = 0$$ $$\left| {\begin{array}{c}{{x^2} + {y^2} - 3x + 1}&{2x + y - 3} \\ 1&1 \end{array}} \right| = 0$$ $${x^2} + {y^2} - 3x + 1 - 2x - y + 3 = 0$$ $${x^2} + {y^2} - 5x - y + 4 = 0$$
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