Chemistry > Stoichiometry > 5.0 Calculation of n-factor

  Stoichiometry
    1.0 The Mole
    2.0 The Limiting Reagent
    3.0 Gravimetric Analysis
    4.0 Volumetric Analysis
    5.0 Calculation of n-factor
    6.0 Redox Reactions
    7.0 Titration
    8.0 Iodimetric and Iodometric Titrations
    9.0 Volume strength peroxide solution
    10.0 Percentage Labeling of Oleum
    11.0 Hardness of Water

5.1 Acid-Base Reaction

According, to the Arrhenius, an acid is a substance that furnishes ${H^ + }$ ion(s) in solution, a base is a substance that furnishes $OH–$ ion(s) in solution and neutralization is a reaction in which ${H^ + }$ ion furnished by acid combines with $OH–$ ions furnished by base. The number of ${H^ + }$ ion(s) furnished per molecule of the acid is its n-factor also called basicity. Similarly the number of $OH–$ ion(s) furnished by the base per molecule is its n-factor, also called acidity.


\[\mathop {HCl}\limits_{(n = 1)} \xrightarrow{{}}{H^ + } + C{l^ - }\]

\[\mathop {{H_2}S{O_4}}\limits_{(n = 1)} \xrightarrow{{}}{H^ + } + HSO_4^ - \]

\[\mathop {{H_2}S{O_4}}\limits_{(n = 2)} \xrightarrow{{}}2{H^ + } + SO_4^{2 - }\]

\[\mathop {{H_3}P{O_4}}\limits_{(n = 1)} \xrightarrow{{}}{H^ + } + {H_2}PO_4^ - \]

\[\mathop {{H_3}P{O_4}}\limits_{(n = 3)} \xrightarrow{{}}3{H^ + } + PO_4^{3 - }\]

\[\mathop {{H_3}P{O_3}}\limits_{(n = 1)} \xrightarrow{{}}{H^ + } + {H_2}PO_3^ - \]

\[\mathop {{H_3}P{O_3}}\limits_{(n = 2)} \xrightarrow{{}}2{H^ + } + HPO_3^ - \]


The n-factor of ${H_3}P{O_3}$ cannot be 3 as it has only two dissociable ${H^ + }$ ions. So, its n-factor or dissociable protons is 1 or 2 as one of the $H-$ atoms is linked with P atom directly.

Similarly,

\[\mathop {C{H_3}COOH}\limits_{(n = 1)} \xrightarrow{{}}C{H_3}CO{O^ - } + {H^ + }\]

n-factor of $C{H_3}COOH$ is 1, because it contains only one dissociable ${H^ + }$ ion.

Now, we will consider the n-factor of some bases.

\[\mathop {NaOH}\limits_{(n = 1)} \xrightarrow{{}}N{a^ + } + O{H^ - }\]

\[\mathop {Ba{{(OH)}_2}}\limits_{(n = 1)} \xrightarrow{{}}{[Ba(OH)]^ - } + O{H^ - }\]

\[\mathop {Ba{{(OH)}_2}}\limits_{(n = 2)} \xrightarrow{{}}B{a^{2 + }} + 2O{H^ - }\]

\[\mathop {Al{{(OH)}_3}}\limits_{(n = 3)} \xrightarrow{{}}A{l^{3 + }} + 3O{H^ - }\]

Similarly, n-factor of $Al{\left( {OH} \right)_3}$ can also be 1 or 2 or 3, depending upon the number of $OH–$ released.

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