Ionic Equilibrium
    8.0 Solubility and Solubility Product

8.0 Solubility and Solubility Product
At constant temperature, the maximum number of moles of solute which can be dissolved in a solvent to obtain one litre of solution (i.e. saturated solution) is called solubility.

Solubility does not depend on amount of substance and volume of solution but depends on the following:

1. Temperature

2. Presence of common ion

3. Nature of solvent

At constant temperature, product of concentrations of ions in a saturated solution of substance is called solubility product of that substance. (Saturated solution is that solution in which further dissolution of even a small amount of salt is not possible).

If we add more $AgCl$ to its saturated solution, an equilibrium will be established

$$AgC{l_{(s)}} \rightleftharpoons A{g^ + } + C{l^ - }$$

$$K = \frac{{\left[ {A{g^ + }} \right]\left[ {C{l^ - }} \right]}}{{\left[ {AgCl} \right]}}$$

As $$K\left[ {AgCl} \right] = {K_c} = \left[ {A{g^ + }} \right]\left[ {C{l^ - }} \right]$$

This ${K_c}$ is given a special name, ${K_{sp}}$ i.e., solubility product.

Therefore, if ionic product is less than ${K_{sp}}$, more of salt dissolves.

If the ionic product is equal to ${K_sp}$ then the solution is saturated and if it is greater than ${K_sp}$, then salt will precipitate out.

Improve your JEE MAINS score
10 Mock Test
Increase JEE score
by 20 marks
Detailed Explanation results in better understanding
Exclusively for
JEE MAINS and ADVANCED
9 out of 10 got
selected in JEE MAINS
Lets start preparing
DIFFICULTY IN UNDERSTANDING CONCEPTS?
TAKE HELP FROM THINKMERIT DETAILED EXPLANATION..!!!
9 OUT OF 10 STUDENTS UNDERSTOOD