7.0 Relation between kinetic energy and temperature

Kinetic energy of any gas is directly proportional to its absolute temperature. Mathematically, $$K.E. \propto T$$For n moles of gas, $$K.E. = \frac{3}{2}nRT$$

Kinetic energy per mole of a gas at temperature $T$ is given by $$K.E. = \frac{3}{2}RT$$ Similarly, K.E. of one molecule of a gas is given by $$K.E. = \frac{3}{2}kT$$ where, $k$ is boltzmann's constant.