Physics > Wave Optics > 4.0 Polarisation

  Wave Optics
    1.0 Introduction
    2.0 Young's double slit experiment
    3.0 Diffraction of light
    4.0 Polarisation

4.2 Brewster's law
According to Brewster's law, when unpolarised light is incident at polarising angle $\left( {{\theta _i}} \right)$ on an interface separating a rarer medium from a denser medium of refractive index $\mu $ such that,
$$\mu = \tan {\theta _i}$$
then the light which is reflected in the rarer medium is completely polarised. The reflected and refracted rays are perpendicular to each other.


Consider an unpolarised light is incident at an angle $\left( {{\theta _i}} \right)$ and undergoes reflection and refraction as shown in the figure.

According to Brewster's law, the reflected and refracted rays are perpendicular to each other.

From the figure we can write,
$$\begin{equation} \begin{aligned} {\theta _i} + 90^\circ + {\theta _r} = 180^\circ \\ {\theta _i} + {\theta _r} = 90^\circ \quad ...(i) \\\end{aligned} \end{equation} $$
From Snell's law,
$${\mu _1}\sin {\theta _i} = {\mu _2}\sin {\theta _r}\quad ...(ii)$$
From equation $(i)$ and $(ii)$ we get,
$$\begin{equation} \begin{aligned} {\mu _1}\sin {\theta _i} = {\mu _2}\sin \left( {90^\circ - {\theta _i}} \right) \\ {\mu _1}\sin {\theta _i} = {\mu _2}\cos {\theta _i} \\ \frac{{\sin {\theta _i}}}{{\cos {\theta _i}}} = \frac{{{\mu _2}}}{{{\mu _1}}} \\ \tan {\theta _i} = \frac{{{\mu _2}}}{{{\mu _1}}} \\\end{aligned} \end{equation} $$ or $${\theta _i} = {\tan ^{ - 1}}\left( {\frac{{{\mu _2}}}{{{\mu _1}}}} \right)$$

When the light is coming from air




$$\mu = \tan {\theta _i}$$

Improve your JEE MAINS score
10 Mock Test
Increase JEE score
by 20 marks
Detailed Explanation results in better understanding
Exclusively for
JEE MAINS and ADVANCED
9 out of 10 got
selected in JEE MAINS
Lets start preparing
DIFFICULTY IN UNDERSTANDING CONCEPTS?
TAKE HELP FROM THINKMERIT DETAILED EXPLANATION..!!!
9 OUT OF 10 STUDENTS UNDERSTOOD