Physics > Alternating Current > 5.0 Power in AC circuit

  Alternating Current
    1.0 Introduction
    2.0 Alternating current and alternating voltage
    3.0 Some important terms
    4.0 Circuit element in AC circuit
    5.0 Power in AC circuit

5.2 Average power

The average rate of doing work (power) in one cycle is known as average power.


It is also known as true power.


Mathematically, $${P_{av}} = \frac{{\int\limits_0^T {Pdt} }}{{\int\limits_0^T {dt} }}$$$${P_{av}} = {V_0}{i_0}\frac{{\int\limits_0^T {\left[ {{{\sin }^2}\omega t\cos \phi - \frac{1}{2}{{\sin }^2}\omega t\sin \phi } \right]} dt}}{{\int\limits_0^T {dt} }}$$$${P_{av}} = \frac{{{V_0}{i_0}\cos \phi \int\limits_0^T {{{\sin }^2}\omega tdt} - \frac{{{V_0}{i_0}\sin \phi }}{2}\int\limits_0^T {\sin 2\omega t} dt}}{{\int\limits_0^T {dt} }}$$$${P_{av}} = \frac{{{V_0}{i_0}\cos \phi \int\limits_0^T {\left( {\frac{{1 - \cos 2\omega t}}{2}} \right)dt} - \frac{{{V_0}{i_0}\sin \phi }}{2}\int\limits_0^T {\sin 2\omega t} dt}}{{\int\limits_0^T {dt} }}$$$${P_{av}} = \frac{{\frac{{{V_0}{i_0}\cos \phi }}{2}\left[ {t - \frac{{\sin 2\omega t}}{{2\omega }}} \right]_0^T + \frac{{{V_0}{i_0}\sin \phi }}{2}\left[ {\frac{{\cos 2\omega t}}{{2\omega }}} \right]_0^T}}{{\left[ t \right]_0^T}}$$$${P_{av}} = \frac{{\frac{{{V_0}{i_0}\cos \phi }}{2}\left[ {\left( {T - \frac{{\sin 2\omega T}}{{2\omega }}} \right) - \left( {0 - 0} \right)} \right] + \frac{{{V_0}{i_0}\sin \phi }}{2}\left[ {\frac{{\cos 2\omega T}}{{2\omega }} - \frac{1}{{2\omega }}} \right]}}{{\left[ {T - 0} \right]}}$$As $T = \frac{{2\pi }}{\omega }$,$${P_{av}} = \frac{{\frac{{{V_0}{i_0}\cos \phi }}{2}\left[ {T - 0} \right] + \frac{{{V_0}{i_0}\sin \phi }}{2}\left[ {\frac{1}{{2\omega }} - \frac{1}{{2\omega }}} \right]}}{T}$$$${P_{av}} = \frac{1}{2}{V_0}{i_0}\cos \phi $$Also, $${P_{av}} = \frac{1}{2}{V_0}{i_0}\cos \phi $$$${P_{av}} = \frac{{{V_0}}}{{\sqrt 2 }}\frac{{{i_0}}}{{\sqrt 2 }}\cos \phi $$$${P_{av}} = {V_{rms}}{i_{rms}}\cos \phi $$

The term $\cos \phi $ is known as power factor.

Improve your JEE MAINS score
10 Mock Test
Increase JEE score
by 20 marks
Detailed Explanation results in better understanding
Exclusively for
JEE MAINS and ADVANCED
9 out of 10 got
selected in JEE MAINS
Lets start preparing
DIFFICULTY IN UNDERSTANDING CONCEPTS?
TAKE HELP FROM THINKMERIT DETAILED EXPLANATION..!!!
9 OUT OF 10 STUDENTS UNDERSTOOD