Motion in Two Dimension
    3.0 Ground to ground projectile motion

3.0 Ground to ground projectile motion

Consider a projectile thrown with velocity $u$ making an angle $\theta$ with the horizontal.


Velocity $u$ is resolved into two perpendicular components i.e. $x$ and $y$ directions.

We will write all the information about the projectile motion for horizontal and vertical direction in two separate columns.

Horizontal motionVertical motion
${u_x} = u\cos \theta $
${u_y} = u\sin \theta $
${a_x} = 0$
${a_y} = - g$
Improve your JEE MAINS score
10 Mock Test
Increase JEE score
by 20 marks
Detailed Explanation results in better understanding
Exclusively for
JEE MAINS and ADVANCED
9 out of 10 got
selected in JEE MAINS
Lets start preparing
DIFFICULTY IN UNDERSTANDING CONCEPTS?
TAKE HELP FROM THINKMERIT DETAILED EXPLANATION..!!!
9 OUT OF 10 STUDENTS UNDERSTOOD