Chemistry > Hydrocarbons > 7.0 Methods of Preparation Alkenes

  Hydrocarbons
    1.0 Introduction
    2.0 Alkanes
    3.0 Methods of Preparation Alkanes
    4.0 Physical Proparties
    5.0 Chemical Properties
    6.0 Alkenes
    7.0 Methods of Preparation Alkenes
    8.0 Physical Proparties
    9.0 Chemical Properties
    10.0 Mechanism Of Some Important Reaction Of Alkenes
    11.0 Alkynes
    12.0 Methods of Preparation Alkynes
    13.0 Physical Properties
    14.0 Chemical Properteis
    15.0 Modern Concept
    16.0 Properteis
    17.0 Mechanism of Electrophilic Substitution Reactions
    18.0 Toluene
    19.0 Alkenyl Benzene

7.1 Dehydrohalgoenation

It is possible to form alkenes by base – induced elimination from alkyl halides

Alcoholic KOH converts alkyl halide into alkene by a reaction called dehydrohalogenation which involves removal of the halogen atom together with a hydrogen atom from a carbon adjacent to the one having the halogen.

Note:

(i) Ease of dehydrohalogenation of alkyl halides is in order 30 > 20 > 10.

(ii) Ease of formation of alkenes is in order

${R_2}C{\text{ }} = {\text{ }}C{R_2} > {\text{ }}{R_2}C{\text{ }} = {\text{ }}CHR{\text{ }} > {\text{ }}{R_2}C{\text{ }} = {\text{ }}C{H_2}or{\text{ }}RCH{\text{ }} = {\text{ }}CHR{\text{ }} > {\text{ }}RCH{\text{ }} = {\text{ }}C{H_2} > {\text{ }}C{H_2} = {\text{ }}C{H_{2}}$

and same is the stability order of alkenes.
Thus by general rule: More stable the alkene, the more easily it is formed
Increasing rate of dehydrohalogenation is in the order.
$RF{\text{ }} < {\text{ }}RCl{\text{ }} < {\text{ }}RBr{\text{ }} < {\text{ }}RI$
Also greater the conjugation, greater is the stability (due to resonance) hence easier is the dehydrohalogenation.
As II is more stable than IV hence dehydrohalogenation of I is easier than that of (III)

In case of elimination of HBr from 1 – bromo – 1 – methyl cyclohexane, loss of bromide provides a tertiary cation. This species is symmetrical and loss of proton from either of the adjacent methylene groups leads to the same product, 1 – methyl – 1 cyclohexene in which the double bond is in the ring (endocyclic) on the other hand loss of proton from the methyl group produces methylene cyclohexane (Y) in which the double bond is outside the ring (exocyclic). By saytzeff rule, the more highly substituted an alkene, the more stable it is hence formation of 1 – methyl – 1 – cyclohexene is favoured.
Formation of less substituted alkene in an elimination reaction is referred to as a Hofmann elimination.

Note:
Hindered base gives Hofmann product as major isomer.



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