Physics > Circular Motion > 5.0 Circular turning of roads

  Circular Motion
    1.0 Introduction
    2.0 Dynamics of circular motion
    3.0 Motion in a vertical circle
    4.0 Rigid body rotating in a vertical circle
    5.0 Circular turning of roads
    6.0 Conical Pendulum
    7.0 Death well
    8.0 Rotor
    9.0 Bending of a cyclist or motorcyclist while taking turn
    10.0 Centrifugal force

5.2 By banking of roads
Circular turn due to friction has speed restrictions i.e. $v \leqslant \sqrt {\mu rg} $.


Therefore, it is not always reliable at circular turns where vehicle is moving at high speed and where sharp turns are involved.

To avoid dependence on friction, the roads are banked at the turn so that the outer part of the road is some what lifted compared to the inner part.

When a jeep of mass $m$ runs on a circular track of radius $R$ which is banked at an angle $\theta $, the necessary centripetal force for circular turn is provided by the component of the normal force.

From FBD we get, $$\begin{equation} \begin{aligned} N\cos \theta = mg\quad ...(i) \\ N\sin \theta = \frac{{m{v^2}}}{R}\quad ...(ii) \\\end{aligned} \end{equation} $$
Dividing equation $(i)$ and $(ii)$ we get, $$\begin{equation} \begin{aligned} \tan \theta = \frac{{{v^2}}}{{Rg}} \\ v = \sqrt {Rg\tan \theta } \\\end{aligned} \end{equation} $$
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