Three Dimensional Coordinate System
    1.0 Introduction
    2.0 Equation of a line in space
    3.0 Distance and Angle between lines and points.
    4.0 Plane
    5.0 Relation between Plane, Line and Point.
    6.0 Intersection of a line and a plane
    7.0 Image of a point in a plane

4.3 Equation of plane passing through a given point and parallel to the two given vectors

This is just the special case of an above-mentioned method to find the equation of plane when a point through which plane pass and the normal vector to the plane is given.

Here the difference is instead of a normal vector to the plane, two vectors parallel to the plane are given. Our approach is to find the normal vector to the plane from these two vectors.

As we know that the cross product of two vectors in the same plane gives a vector perpendicular to that plane in which two vectors lie.

Therefore, the cross product of two given vectors parallel to the plane will give us the normal vector to the plane.

Let us assume the plane passes through a point $A$ with position vector $\overrightarrow a $ and is parallel to the given vectors $\overrightarrow b $ and $\overrightarrow c $ and $\overrightarrow r $ be the position vector of any point $P$ in the plane.

Therefore, we can write $$\overrightarrow {AP} = \overrightarrow {OP} - \overrightarrow {OA} = \overrightarrow r - \overrightarrow a $$ Since, the vectors $\overrightarrow r - \overrightarrow a ,\;\overrightarrow b ,\;\overrightarrow c $ are coplanar. Thus, $$\begin{equation} \begin{aligned} \left( {\overrightarrow r - \overrightarrow a } \right).\;\left( {\overrightarrow b \times \;\overrightarrow c } \right) = 0 \\ \overrightarrow r .\left( {\overrightarrow b \times \;\overrightarrow c } \right) = \overrightarrow a .\left( {\overrightarrow b \times \;\overrightarrow c } \right) \\\end{aligned} \end{equation} $$
\[\left[ {\begin{array}{c} {\overrightarrow r }&{\overrightarrow b }&{\overrightarrow c } \end{array}} \right] = \left[ {\begin{array}{c} {\overrightarrow a }&{\overrightarrow b }&{\overrightarrow c } \end{array}} \right]\]
which is the required vector equation of plane.

Similarly, the Cartesian equation of plane passing through a given point and parallel to the two given lines whose direction ratios are $\left( {{\alpha _1},{\beta _1},{\gamma _1}} \right)$ and $\left( {{\alpha _2},{\beta _2},{\gamma _2}} \right)$ is
\[\left| {\begin{array}{c} {x - {x_1}}&{y - {y_1}}&{z - {z_1}} \\ {{\alpha _1}}&{{\beta _1}}&{{\gamma _1}} \\ {{\alpha _2}}&{{\beta _2}}&{{\gamma _2}} \end{array}} \right| = 0\]
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