Physics > Superposition of Waves > 3.0 Standing or Stationary Wave

  Superposition of Waves
    1.0 Introduction
    2.0 Interference of Waves
    3.0 Standing or Stationary Wave
    4.0 Longitudinal stationary wave in an organ pipe
    5.0 Beats
    6.0 Questions

3.3 Melde's Experient
Longitudinal mode

In longitudinal mode, the prongs of the tuning fork vibrate in a direction parallel to the length of the string.

In the longitudinal mode when tuning fork completes one vibration, the string completes only half the vibration. So, the frequency of the string is half of that of the fork. $$\begin{equation} \begin{aligned} {f_s} = \frac{{{f_f}}}{2}\quad ...(i) \\ \frac{{n\lambda }}{2} = L \\ \frac{v}{{{f_s}}} = \frac{{2L}}{n} \\ {f_s} = \frac{n}{{2L}}\sqrt {\frac{T}{\mu }} \quad ...(ii) \\\end{aligned} \end{equation} $$ From equation $(i)$ & $(ii)$ we get, $${f_f} = \frac{n}{L}\sqrt {\frac{T}{\mu }} $$

Transverse mode

In transverse mode, the prongs of the tuning fork vibrate in a direction perpendicular to the length of the string.

In the transverse mode when tuning fork completes one vibration, the string also completes one vibration. So, the frequency of the string is equal to that of the fork. $$\begin{equation} \begin{aligned} {f_s} = {f_f}\quad ...(i) \\ \frac{{n\lambda }}{2} = L \\ \frac{v}{{{f_s}}} = \frac{{2L}}{n} \\ {f_s} = \frac{n}{{2L}}\sqrt {\frac{T}{\mu }} \quad ...(ii) \\\end{aligned} \end{equation} $$ From equation $(i)$ & $(ii)$ we get, $${f_f} = \frac{n}{{2L}}\sqrt {\frac{T}{\mu }} $$

Note: The number of loops in the transverse mode is twice that in the longitudinal mode.
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