Inverse Trigonometric Function
    1.0 Introduction
    2.0 Inverse Trigonometric function
    3.0 Properties

3.5 Property 5
(i) ${\sin ^{ - 1}}x + {\cos ^{ - 1}}x = \frac{\pi }{2}; - 1 \leqslant x \leqslant 1$

Proof: Put $$\begin{equation} \begin{aligned} {\sin ^{ - 1}}x = A \\ \Rightarrow x = \sin A \\ {\cos ^{ - 1}}x = B \\ x = \cos B \\ \sin A = \cos B \\ \sin A = \sin \left( {\frac{\pi }{2} - B} \right) \\\end{aligned} \end{equation} $$where $\left( {A,\left( {\frac{\pi }{2} - B} \right) \in \left[ { - \frac{\pi }{2},\frac{\pi }{2}} \right]} \right)$
$$\begin{equation} \begin{aligned} A = \frac{\pi }{2} - B \\ A + B = \frac{\pi }{2} \\\end{aligned} \end{equation} $$
Putting the values of $A$ and $B$ we get $${\sin ^{ - 1}}x + {\cos ^{ - 1}}x = \frac{\pi }{2}$$

(ii) ${\tan ^{ - 1}}x + {\cot ^{ - 1}}x = \frac{\pi }{2};x \in R$

(iii) ${\text{cose}}{{\text{c}}^{ - 1}}x + {\sec ^{ - 1}}x = \frac{\pi }{2};\;\left| x \right| \geqslant 1$
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