2.2 Variation of acceleration due to gravity $(g)$ due to altitude

1.1 Characteristics of gravitational force
1.2 Universal gravitational constant
1.3 Principle of superposition of gravitation
1.4 Gravity
1.5 Acceleration due to gravity
1.6 Relation between $g$ and $G$

2.1 Variation of acceleration due to gravity $(g)$ due to shape of the earth
2.2 Variation of acceleration due to gravity $(g)$ due to altitude
2.3 Variation of acceleration due to gravity $(g)$ due to depth
2.4 Variation of acceleration due to gravity $(g)$ due to rotation of earth

3.1 Gravitational field due to a point mass
3.2 Gravitational field due to a uniform solid sphere
3.3 Gravitational field due to a uniform spherical shell
3.4 Gravitatioal field due to a uniform circular ring at a point on its axis

4.1 Gravitational potential due to a point mass
4.2 Gravitational potential due to a uniform solid sphere
4.3 Gravitational potential due to a uniform thin spherical shell
4.4 Gravitational potential due to a uniform ring at a point on its centre
4.5 Relation between gravitational field and gravitational potential

5.1 Gravitational potential energy for a system of particles
5.2 Gravitational potential energy of a body on earth's surface

6.1 Orbital speed of satellite
6.2 Time period of a satellite
6.3 Angular momentum of a satellite
6.4 Energy of a satellite
6.5 Types of satellite
6.6 Binding energy
6.7 Escape velocity
6.8 Weightlessness

7.1 Kepler's first law
7.2 Kepler's second law
7.3 Kepler's third law

Consider a mass $m$ at a height $h$ from the surface of the earth.

Now, the force acting on the mass due to gravity is,

$$F = \frac{{G{M_e}m}}{{{{\left( {R + h} \right)}^2}}}$$

where,

$G:$ Universal gravitational constant

$M:$ Mass of the earth

$m:$ Mass of the body

$R:$ Radius of the earth

$h:$ Height

$$g' = \frac{{GM}}{{{{\left( {R + h} \right)}^2}}}$$ $$g' = \frac{{GM}}{{{R^2}}}{\left[ {\frac{{R + h}}{R}} \right]^{ - 2}}$$ $$g' = g{\left[ {1 + \frac{h}{R}} \right]^{ - 2}}$$

As $\left( {R > > h} \right)$. So,

$$g' = g\left[ {1 - \frac{{2h}}{R}} \right]$$

Therefore, when we move above the surface of earth acceleration due to gravity $g$ goes on decreasing.