Maths > Matrices and Determinants > 3.0 Special Matrices

  Matrices and Determinants
    1.0 Introduction
    2.0 Algebra of Matrices
    3.0 Special Matrices
    4.0 Determinant of a square matrix
    5.0 Adjoint of a square Matrix
    6.0 Inverse of a Matrix
    7.0 Types of Equations Homogenous & Non-Homogenous
    8.0 Cramer's rule
    9.0 Types of Linear Equations

3.9 (i) Involuntary Matrix:
A matrix such that ${A^2} = I$ is called an involuntary matrix.



Question 7.

Show that the matrix $A = \left[ {\begin{array}{c} { - 5}&{ - 8}&0 \\ 3&5&0 \\ 1&2&{ - 1} \end{array}} \right]$ is involuntary.

Solution:

${A^2} = A.A = \left[ {\begin{array}{c} { - 5}&{ - 8}&0 \\ 3&5&0 \\ 1&2&{ - 1} \end{array}} \right] \times \left[ {\begin{array}{c} { - 5}&{ - 8}&0 \\ 3&5&0 \\ 1&2&{ - 1} \end{array}} \right]$

$ = \left[ {\begin{array}{c} {25 - 24 + 0}&{40 - 40 + 0}&{0 + 0 + 0} \\ { - 15 + 15 + 0}&{ - 24 + 25 + 0}&{0 + 0 + 0} \\ { - 5 + 6 - 1}&{ - 8 + 10 - 2}&{0 + 0 + 1} \end{array}} \right]$

$ = \left[ {\begin{array}{c} 1&0&0 \\ 0&1&0 \\ 0&0&1 \end{array}} \right]$

$ = I$

Hence the given matrix $A$ is involuntary.
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