Maths > Matrices and Determinants > 3.0 Special Matrices

  Matrices and Determinants
    1.0 Introduction
    2.0 Algebra of Matrices
    3.0 Special Matrices
    4.0 Determinant of a square matrix
    5.0 Adjoint of a square Matrix
    6.0 Inverse of a Matrix
    7.0 Types of Equations Homogenous & Non-Homogenous
    8.0 Cramer's rule
    9.0 Types of Linear Equations

3.7 (g) Idempotent Matrix :
A square matrix $A$ is called idempotent provided it satisfies the relation ${A^2} = A$.


Question 5.

Prove that the matrix $A = \left[ {\begin{array}{c} 2&{ - 2}&{ - 4} \\ { - 1}&3&4 \\ 1&{ - 2}&{ - 3} \end{array}} \right]$ is idempotent.

Solution:

${A^2} = A.A = \left[ {\begin{array}{c} 2&{ - 2}&{ - 4} \\ { - 1}&3&4 \\ 1&{ - 2}&{ - 3} \end{array}} \right] \times \left[ {\begin{array}{c} 2&{ - 2}&{ - 4} \\ { - 1}&3&4 \\ 1&{ - 2}&{ - 3} \end{array}} \right]$

$ = \left[ {\begin{array}{c} {2.2 + \left( { - 2} \right).\left( { - 1} \right) + \left( { - 4} \right).1}&{2\left( { - 2} \right) + \left( { - 2} \right).3 + \left( { - 4} \right).\left( { - 2} \right)}&{2\left( { - 4} \right) + \left( { - 2} \right).4 + \left( { - 4} \right).\left( { - 3} \right)} \\ {\left( { - 1} \right).2 + 3.\left( { - 1} \right) + 4.1}&{\left( { - 1} \right).\left( { - 2} \right) + 3.3 + 4.\left( { - 2} \right)}&{\left( { - 1} \right).\left( { - 4} \right) + 3.4 + 4.\left( { - 3} \right)} \\ {1.2 + \left( { - 2} \right).\left( { - 1} \right) + \left( { - 3} \right).1}&{1.\left( { - 2} \right) + \left( { - 2} \right).3 + \left( { - 3} \right).\left( { - 2} \right)}&{1.\left( { - 4} \right) + \left( { - 2} \right).4 + \left( { - 3} \right).\left( { - 3} \right)} \end{array}} \right]$

$ = \left[ {\begin{array}{c} 2&{ - 2}&{ - 4} \\ { - 1}&3&4 \\ 1&{ - 2}&{ - 3} \end{array}} \right] = A$

Hence the matrix $A$ is idempotent.
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