Chemistry > Electrochemistry > 13.0 Laws of Electrolysis

  Electrochemistry
    1.0 Introduction
    2.0 Conductors and Non-Conductors
    3.0 Electrochemical Cells
    4.0 Electrolysis and electrode Reactions
    5.0 Electrochemical Cell
    6.0 Electrode Potential
    7.0 Nature of Electrodes
    8.0 IUPAC Cell Representation and Convention
    9.0 Standard Cell EMF and Standard Reduction Potential
    10.0 Electropositive Character of Metals
    11.0 Difference between EMF and potential difference
    12.0 Nernst Equation
    13.0 Laws of Electrolysis
    14.0 Electromotive Force
    15.0 Thermodynamics of the Cells
    16.0 Concentration Cells
    17.0 Battery
    18.0 Fuel Cell

13.1 Faraday's first law
This law states that the mass of substance liberated or deposited at the electrode depends on the quantity of electric charge passed through it or mass deposited or liberated at the electrode is directly proportional to the amount of electricity passed through it.
Mathematically,$$W\propto Q$$
where
$W$ is the mass of the ions deposited and

$Q$ is the quantity of electricity in coulombs, which is equal to product of current (in amperes) and time (in seconds)
$$W = Z \times I \times t$$
$Z$ is the constant, known as electrochemical equivalent (ECE) of the ion deposited.


When $1$ ampere current is passed for $1$ second then $W=Z$ so we can define $Z$ (called electrochemical equivalent) as mass of ion deposited by passing current of $1$ ampere for$1$ second (i.e., by passing $1$ coulomb of charge). Its unit is $Kg{C^{ - 1}}$

$1\ F$ of charge $=$ charge on one mole of electron

$$\begin{equation} \begin{aligned} = {N_A} \times e \\ = 6.023 \times {10^{23}} \times 1.602 \times {10^{ - 19}} \\ = 96514.8C \approx 96500C \\\end{aligned} \end{equation} $$

$=$ the charge which discharges equivalent weight of ion.

so $$F = {N_A} \times e$$
therefore, $$1\ C\ of\ charge = \frac{E}{{96500}}g\ \ of\ ion\ =\ Z$$
Now substitute the value of $Z$ in the reaction
$$\begin{equation} \begin{aligned} W = ZIt = \frac{{EIt}}{{96500}} \\ \frac{W}{E} = \frac{{It}}{{9650}} = \frac{Q}{{96500}} = \frac{Q}{F} \\\end{aligned} \end{equation} $$
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