Chemistry > p Block Elements > 3.0 Compounds of boron
p Block Elements
1.0 Group $13$ – The Boron Family
2.0 Boron
3.0 Compounds of boron
4.0 Compounds of Aluminium
5.0 Group $14$ – The Carbon family
6.0 Allotropes of Carbon
7.0 Compounds of Carbon
8.0 Properties of Silicon
9.0 Group $15$-The Nitrogen Family
10.0 Oxides of nitrogen
10.1 Nitrogen Oxide $N_2O$ or Laughing gas (Neutral)
10.2 Nitric Oxide $NO$ (Neutral)
10.3 Nitrogen trioxide $N_2O_3$
10.4 Nitrogen dioxide or Di-nitrogen tetroxide $NO_2$ or $N_2O$
10.5 Nitrogen pentaoxide $N_2O_5$
11.0 Oxyacids of Nitrogen
11.1 Nitric acid $HNO_3$
11.2 Oxidation of Metalloid and Inorganic compounds by Nitric acid
11.3 Action of Metals & Proteins
12.0 Phosphorus
13.0 Oxygen
14.0 Sulphur
3.1 Borax
10.2 Nitric Oxide $NO$ (Neutral)
10.3 Nitrogen trioxide $N_2O_3$
10.4 Nitrogen dioxide or Di-nitrogen tetroxide $NO_2$ or $N_2O$
10.5 Nitrogen pentaoxide $N_2O_5$
11.2 Oxidation of Metalloid and Inorganic compounds by Nitric acid
11.3 Action of Metals & Proteins
It is a white crystalline solid of formula $Na_2B_4O_7.10H_2O$. It contains the tetranuclear units $[B_4O_5(OH)_4]^{2-}$ and correct formula is $Na_2[B_4O_5(OH)_4].8H_2O$.
Properties:
1. Borax dissolves in water to give an alkaline solution. $$N{a_2}{B_4}{O_7} + 7{H_2}O \to 2NaOH + 4{H_3}B{O_3}\left( {{\text{Orthoboric acid}}} \right)$$
2. Borax Bead Test: On heating, borax first loses water molecules and swells up. On further heating it turns into a transparent liquid, which solidifies into glass like material known as borax bead.
$$N{a_2}{B_4}{O_7}.10{H_2}O\mathop \to \limits^\Delta N{a_2}{B_4}{O_7}\left( {{\text{Sodium metaborate}}} \right)\mathop \to \limits^{740^\circ C} 2NaB{O_2} + {B_2}{O_3}\left( {{\text{Boric anhydride}}} \right)$$
When hot glassy mass is brought in contact with coloured salt and heated again in the flame, $B_2O_3$ displaces. The volatile oxides combines with basic oxides to form metaborates. Metaborates of basic radicals have characteristic colours in hot oxidizing/reducing and cold oxidizing/reducing flames.
$$CuS{O_4} + {B_2}{O_3} \to CuO.{B_2}{O_3}\left( {{\text{Blue}}} \right) + S{O_3}$$
3. It is a useful primary standard for titration against acids.
$$N{a_2}[{B_4}{O_5}\left( {OH{)_4}} \right].8{H_2}O + 2HCl \to 2NaCl + 4{H_3}B{O_3} + 5{H_2}O$$
One of the products $H_3BO_3$ is a weak acid. Thus, the indicator used to detect the end point of reaction is methyl orange.