Physics > Motion in One Dimension > 6.0 Analysis of motion through graph

  Motion in One Dimension
    1.0 Introduction
    2.0 Kinematic variables
    3.0 Motion in one dimension
    4.0 Derivation of the kinematics equation
    5.0 Vertical motion under gravity
    6.0 Analysis of motion through graph
    7.0 Relative motion
    8.0 Simultaneous motion of two bodies
    9.0 River boat problem
    10.0 Aircraft-wind problem
    11.0 Rain problem

6.3 Area under the graph

The area under the graph is the product of the horizontal axis and the vertical axis.


Area under $v-t$ graph


The product of velocity and time gives displacement.

So, the area under the graph will give displacement.

Area $ = \frac{1}{2}ab$

So,
Displacement $= \frac{1}{2}ab$

Similarly area under speed$-$time graph gives distance traveled.

Note: Area under velocity$-$time graph gives displacement as well as distance.


Illustration:


As velocity is a vector quantity it can be both positive and negative.

Negative velocity means velocity is in opposite direction.

$A_1, \ A_2$ and $A_3$ are the areas of different section.

$A_1>0$ above the time axis
$A_2<0$ below the time axis
$A_3>0$ above the time axis

Displacement $=A_1+A_2+A_3$

When area under $v-t$ graph is added with proper sign, it gives displacement.

In other words, vector sum of area gives displacement.

Distance $ = \left| {{A_1}} \right| + \left| {{A_2}} \right| + \left| {{A_3}} \right|$

Scalar sum of area under $(v-t)$ graph gives displacement.

Improve your JEE MAINS score
10 Mock Test
Increase JEE score
by 20 marks
Detailed Explanation results in better understanding
Exclusively for
JEE MAINS and ADVANCED
9 out of 10 got
selected in JEE MAINS
Lets start preparing
DIFFICULTY IN UNDERSTANDING CONCEPTS?
TAKE HELP FROM THINKMERIT DETAILED EXPLANATION..!!!
9 OUT OF 10 STUDENTS UNDERSTOOD