Motion in One Dimension
1.0 Introduction
2.0 Kinematic variables
2.1 Distance and displacement
2.2 Average speed and velocity
2.3 Instantaneous speed and velocity
2.4 Average and instantaneous acceleration
3.0 Motion in one dimension
3.1 Motion in a straight line with uniform velocity
3.2 Motion in a straight line with uniform acceleration
3.3 Motion in a straight line with non-uniform acceleration
4.0 Derivation of the kinematics equation
5.0 Vertical motion under gravity
5.1 Basic terminologies for motion under gravity
5.2 Detailed concept of motion under gravity
5.3 Solved examples
6.0 Analysis of motion through graph
6.1 Displacement - time graph
6.2 Velocity - time graph
6.3 Area under the graph
6.4 Solved examples
7.0 Relative motion
7.1 Relative displacement
7.2 Relative velocity
7.3 Relative acceleration
7.4 Illustration of relative motion
7.5 Application of relative motion
8.0 Simultaneous motion of two bodies
9.0 River boat problem
9.1 Downstream
9.2 Upstream
9.3 Crosses the river in shortest interval of time
9.4 Reaches the point just opposite from where he started
9.5 River-man problem
9.6 Solved examples
10.0 Aircraft-wind problem
11.0 Rain problem
11.1 Solved examples
2.2 Average speed and velocity
2.3 Instantaneous speed and velocity
2.4 Average and instantaneous acceleration
3.2 Motion in a straight line with uniform acceleration
3.3 Motion in a straight line with non-uniform acceleration
5.2 Detailed concept of motion under gravity
5.3 Solved examples
6.2 Velocity - time graph
6.3 Area under the graph
6.4 Solved examples
7.2 Relative velocity
7.3 Relative acceleration
7.4 Illustration of relative motion
7.5 Application of relative motion
9.2 Upstream
9.3 Crosses the river in shortest interval of time
9.4 Reaches the point just opposite from where he started
9.5 River-man problem
9.6 Solved examples
Question: Rain drops are falling vertically with respect to ground with a speed of $4\ m/s$. If a boy starts running with a speed of $3\ m/s$ in horizontal direction. Find the direction in which he should hold the umbrella.
Solution: Writing all the information as below,
${\overrightarrow v _R} = - 4\widehat j$
${\overrightarrow v _B} = 3\widehat i$
From the concept of relative motion we can write,
$${\overrightarrow v _{RB}} = {\overrightarrow v _R} - {\overrightarrow v _B}$$$${\overrightarrow v _{RB}} = - 4\widehat j - 3\widehat i$$or$${\overrightarrow v _{RB}} = - 3\widehat i - 4\widehat j$$
The man holds the umbrella in the direction of ${\overrightarrow v _{RB}}$.
Therefore,
$$\tan \theta = \frac{3}{4}$$$$\theta = 37^\circ $$
The boy will hold the umbrella making angle of $37^\circ$ with the vertical.
Question: A man is coming down on an incline of angle $30^\circ$. When he walks with a speed of $2\sqrt 3 \,m/s$ he keeps his umbrella vertical to protect himself from the rain. The actual speed of the rain is $5\ m/s$. Find the velocity of the rain.
Solution:
$\left| {{{\overrightarrow v }_R}} \right| = 5\,m/s$
${\overrightarrow v _M} = 2\sqrt 3 \left( {\cos 30^\circ \widehat i - \sin 30^\circ \widehat j} \right)$
${\overrightarrow v _{RM}} = a\widehat j$ (As he keeps his umbrella vertical).
Let the velocity of the rain be,
$${\overrightarrow v _R} = b\widehat i + c\widehat j$$Also, $$\sqrt {{b^2} + {c^2}} = 5 \quad ...(i)$$
From the concept of relative motion we can write,
$${\overrightarrow v _{RM}} = {\overrightarrow v _R} - {\overrightarrow v _M}$$$$a\widehat j = \left( {b\widehat i + c\widehat j} \right) - \left[ {2\sqrt 3 \left( {\cos 30^\circ \widehat i + \sin 30^\circ \widehat j} \right)} \right]$$$$a\widehat j = \left( {b - 3} \right)\widehat i + \left( {c + \sqrt 3 } \right)\widehat j$$So, $$b = 3\quad ...(ii)$$ From equation $(i)$ and $(ii)$ we get,
$$\sqrt {{3^2} + {c^2}} = 5$$$$9 + {c^2} = 25$$$${c^2} = 16$$$$c = \pm 4$$
So, the velocity of the rain is,
$${\overrightarrow v _R} = 3\widehat i \pm 4\widehat j$$