Physics > Refraction of Light > 6.0 Total internal reflection
Refraction of Light
1.0 Introduction
2.0 Laws of refraction
3.0 Apparent shift of an object
4.0 Thin lenses
4.1 Sign convention
4.2 Some important terms
4.3 Ray tracing
4.4 Image formed by covex lens
4.5 Image formed by concave lens
5.0 Lens makers formula & Other Functions of lens.
5.1 Thin Lens Formula
5.2 Magnification and Power of lens
5.3 Combination of lenses
5.4 Displacement method to find focal length.
5.5 Silvering of lens
6.0 Total internal reflection
7.0 Refraction through prism
8.0 Scattering of light
9.0 Optical instruments
9.1 Spectrometer
9.2 Simple microscope
9.3 Compound microscope
9.4 Astronomical telescope (Refracting type)
9.5 Terrestrial telescope
9.6 Galileo's terrestrial telescope
9.7 Reflecting type telescope
6.2 Application of total internal reflection
4.2 Some important terms
4.3 Ray tracing
4.4 Image formed by covex lens
4.5 Image formed by concave lens
5.2 Magnification and Power of lens
5.3 Combination of lenses
5.4 Displacement method to find focal length.
5.5 Silvering of lens
9.2 Simple microscope
9.3 Compound microscope
9.4 Astronomical telescope (Refracting type)
9.5 Terrestrial telescope
9.6 Galileo's terrestrial telescope
9.7 Reflecting type telescope
- The brilliance of diamond
- Mirages in deserts
Due to heating of the earth, the refractive index of air near the surface of earth becomes lesser than above it. Light from distant objects reaches the surface of earth with $i > {\theta _c}$, so that the total internal reflection takes place and we see the image of an object along with the object as seen in figure creating an illusion of water near the object.
- The working of optical fibre
- A diver in water at a depth $d$ sees the world outside through a horizontal circle of radius $r$.
If $i \geqslant {\theta _c}$ (total internal reflection takes place).
If $i < {\theta _c}$ (refraction takes place and the diver can see the whole world outside).
Using Snell's law,
$$\mu \sin i = \sin r$$
For, $i = {\theta _c}$ (critical angle)
$$r = 90^\circ $$
So, $$\begin{equation} \begin{aligned} \mu \sin {\theta _c} = 1 \\ \sin {\theta _c} = \frac{1}{\mu } \\\end{aligned} \end{equation} $$
From $\Delta AOB$ we can write,
$$\begin{equation} \begin{aligned} \tan i = \frac{r}{d} \\ r = d\tan i \\\end{aligned} \end{equation} $$
So, $$r = \frac{d}{{\sqrt {{\mu ^2} - 1} }}$$