Physics > Refraction of Light > 2.0 Laws of refraction

  Refraction of Light
    1.0 Introduction
    2.0 Laws of refraction
    3.0 Apparent shift of an object
    4.0 Thin lenses
    5.0 Lens makers formula & Other Functions of lens.
    6.0 Total internal reflection
    7.0 Refraction through prism
    8.0 Scattering of light
    9.0 Optical instruments

2.1 Refraction from a spherical surface
The portion of a refracting medium whose curved surface forms the part of a sphere is known as spherical refracting surface.

Spherical refracting surface are of two types,

  • Convex refracting spherical surface


  • Concave refracting spherical surface


Note:

Sign conventions for spherical refracting surface are same as those for spherical mirrors.

Consider two transparent media having indices of refraction ${\mu _1}$ and ${\mu _2}$, where the boundary between the two media is a spherical surface of radius $R$.

Assume ${\mu _2} > {\mu _1}$,

Let us consider a single ray leaving point $O$ and forms a image at point $I$ as shown.



$CP$: Normal
$OP$: Incident ray
$PI$: Refracted ray
$i$: Angle of incidence
$r$: Angle of refraction
$MO$: $-u$
$MI$: $+v$
$MC$: $+R$

From Snell's law we can write,
$${\mu _1}\sin i = {\mu _2}\sin r$$
As (angle $i$ and $r$ are very small). So,
$${\mu _1}i = {\mu _2}r$$ or $$\frac{i}{r} = \frac{{{\mu _2}}}{{{\mu _1}}}\quad ...(i)$$
In $\Delta POC$,
$$\alpha + \beta = i\quad ...(ii)$$
In $\Delta PCI$,
$$\gamma + r = \beta $$ or $$r = \beta - \gamma \quad ...(iii)$$

Dividing equation $(ii)$ and $(iii)$ we get,
$$\frac{i}{r} = \left( {\frac{{\alpha + \beta }}{{\beta - \gamma }}} \right)$$
Using equation $(i)$,
$$\frac{{{\mu _2}}}{{{\mu _1}}} = \left( {\frac{{\alpha + \beta }}{{\beta - \gamma }}} \right)$$
$$\begin{equation} \begin{aligned} {\mu _2}\beta - {\mu _2}\gamma = {\mu _1}\alpha + {\mu _1}\beta \\ \beta \left( {{\mu _2} - {\mu _1}} \right) = {\mu _1}\alpha + {\mu _2}\gamma \quad ...(iv) \\\end{aligned} \end{equation} $$
Now we can write,
$$\begin{equation} \begin{aligned} \tan \alpha = \frac{{PN}}{{NO}}\quad {\text{or}}\quad \tan \alpha = \frac{{PN}}{{MO}} \\ \tan \beta = \frac{{PN}}{{NC}}\quad {\text{or}}\quad \tan \beta = \frac{{PN}}{{MC}} \\ \tan \gamma = \frac{{PN}}{{NI}}\quad {\text{or}}\quad \tan \gamma = \frac{{PN}}{{MI}} \\\end{aligned} \end{equation} $$
As angles $\alpha $, $\beta $ & $\gamma $ are very small due to paraxial approximation.
\[\left. \begin{gathered} \tan \alpha \approx \alpha = \frac{{PN}}{{MO}} \hspace{1em} \\ \tan \beta \approx \beta = \frac{{PN}}{{MC}} \hspace{1em} \\ \tan \gamma \approx \gamma = \frac{{PN}}{{MI}} \hspace{1em} \\\end{gathered} \right\}\quad ...(v)\]

From equation $(iv)$ and $(v)$ we get,
$$\frac{{PN}}{{MC}}\left( {{\mu _2} - {\mu _1}} \right) = {\mu _1}\left( {\frac{{PN}}{{MO}}} \right) + {\mu _2}\left( {\frac{{PN}}{{MI}}} \right)$$
or
$$\left( {\frac{{{\mu _2} - {\mu _1}}}{{MC}}} \right) = \frac{{{\mu _1}}}{{MO}} + \frac{{{\mu _2}}}{{MI}}$$
As $\left( {MC = + R,\;MO = - u,\;MI = + v} \right)$. So,
$$\frac{{{\mu _2} - {\mu _1}}}{{ + R}} = \frac{{{\mu _1}}}{{ - u}} + \frac{{{\mu _2}}}{v}$$
So,
$$\frac{{{\mu _2}}}{v} - \frac{{{\mu _1}}}{u} = \frac{{{\mu _2} - {\mu _1}}}{R}$$

This formula is valid for both convex and concave spherical surfaces.
Improve your JEE MAINS score
10 Mock Test
Increase JEE score
by 20 marks
Detailed Explanation results in better understanding
Exclusively for
JEE MAINS and ADVANCED
9 out of 10 got
selected in JEE MAINS
Lets start preparing
DIFFICULTY IN UNDERSTANDING CONCEPTS?
TAKE HELP FROM THINKMERIT DETAILED EXPLANATION..!!!
9 OUT OF 10 STUDENTS UNDERSTOOD